Question

in the figure (not to scale) ABCD is an isoceles trapezium,AB||CD,AB=9cm,CD=12cm and AP:PD=BQ:QC=1:2 then PQ is

Answer 1

Answer:

PQ= 10cm

Step-by-step explanation:

Here AP/PD= BQ/CD=1/2

prove that ,AP||PQ||CD

In ∆OAB a∆ ODC AB||DC

OA/AD = OB /BC =AB/CD

a/a+a+AD =3/4

3AD =a

a=AD=a/3

AP= a/9 BQ=b/9. PD=2a QC= 2b/9

In ∆oab and ∆opq

Ab/PQ = a/a+AP

PQ=10/9×9 =10 cm

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