in the figure, O is the center of a circle passing through A, B, C and D and angle ADC=120. Find the value of x?
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Answered by
21
its simple
x+120=180
x=60
x+120=180
x=60
Answered by
34
x=30
as
cda +cba =180 opp angles in a cyclic quad
cba=60
acb=90 angles in a semicircle=90
as
cda +cba =180 opp angles in a cyclic quad
cba=60
acb=90 angles in a semicircle=90
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