In the figure, O is the center of the circle. If l(AC)=33, l (CB)=44, then l (CO)=?
Answers
Answered by
5
By using the theorem of pythagoras
(CO)^2 = (CB)^2 + (AC)^2
(CO)^2 = 44^2 + 33^2
= 1036 + 1089
(CO)^2 = 31025
(CO) = √31025
(CO) = 55
Therefore l(CO) = 55 unit
(CO)^2 = (CB)^2 + (AC)^2
(CO)^2 = 44^2 + 33^2
= 1036 + 1089
(CO)^2 = 31025
(CO) = √31025
(CO) = 55
Therefore l(CO) = 55 unit
Answered by
7
27.5
Step-by-step explanation:
by pythagoras theorem
(ab)^2 = ( cb)^2 + ( ac)^2
( ab )^2= (44)^2+ (33)^2
( ab)^2 = 1036+ 1089
( ab )^2 = 31025
(ab)^2= square root of 31025
(ab) =55
ao = ab ÷2
55÷2= 27.5
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