In the figure,O is the centre of circle and PR=QR , angle PQR ?
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Given, ∠POR=120o
Hence, ∠POR=2∠PQR (half angle property)
∠PQR=21×120o=60o
PQRS is a cyclic quadrilateral
∴∠PQR+∠PSR=180o∠PSR=180−60∠PSR=120o
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