In the figure,O is the centre of circle m angle AOB =75° Find m (arc ACB) and m (arc ADB )
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Answer:
The measure of an inscribed angle is half of the measure of the arc intercepted by it.
∴∠ACB=
2
1
m(arcAB)
⇒m(arcAB)=2∠ACB=2×65
o
=130
o
∴m(arcACB)=360
o
−m(arcAB)=360
o
−130
o
=230
o
Hence, the correct answer is 230
o
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