In the figure. O is the centre of the circle.
5.
m<ROQ = 110
Find m<QPT.
Answers
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Step-by-step explanation:
In the figure, O is the centre of the circle. ∠POQ=100
∘
;∠POR=11O
∘
; then ∠QPR equals :
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Answer
Correct option is
D
75
∘
∠QOR+∠QOP+∠POR=360
o
⇒∠QOR=360−100−110=150
o
Angle subtended at the center is twice the angle subtended anywhere on the arc.
⇒∠QPR=
2
1
∠QOR=75
o
So option D is the right answer.
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