Question

In the figure, O is the centre of
the circle and PR = QR. What is
the measure of ∆PQR?

answer fast pls!!!!​

Answer 1

Answer:

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Step-by-step explanation:

Given:

O is the centre

and PR = QR

To Find:

∆PQR

Solution:

Since, O is the centre and R lies on the circle

Therefore, ∆PRQ = 90° --- equation 1

And PR = QR

Therefore, ∆RPQ = ∆RQP --- equation 2

By Area of Triangle,

∆RPQ + ∆RQP + ∆PRQ = 180°

∆RQP + ∆RQP + 90° = 180° [ By equation 1 ]

∆RQP + ∆RQP = 180° - 90° [ By equation 2 ]

2∆PQR = 90°

Therefore, ∆PQR = 90° / 2 = 45°

So, ∆PQR = 45°

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