Math, asked by Rajat111111, 1 year ago

In the figure , O is the centre of the circle. Find angle CBD

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Answered by tanishka6
138
°.° ABCP is a cyclic quadrilateral
.•. angle APC = angle CBD
angle APC = ½angle AOC
=> angle APC = 50°
•.• angle APC = angle CBD
=> angle CBD = 50°

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Answered by MeenakshiG
1

Answer:

In the given figure the angle CBD is equal to 50°.

Step-by-step explanation:

Step 1

ABCP is a cyclic quadrilateral.

A cyclic quadrilateral is one in which all the vertices of the quadrilateral lie on the circumference of a single circle.

Angle APC is equal to angle CBD.

∠APC = ∠CBD

Step 2

Angle APC = \frac{1}{2}angle AOC

∠AOC = 100°  ( Given )

∠APC = 50°

Therefore, ∠CBD = 50°

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