In the figure , O is the centre of the circle. Find angle CBD
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°.° ABCP is a cyclic quadrilateral
.•. angle APC = angle CBD
angle APC = ½angle AOC
=> angle APC = 50°
•.• angle APC = angle CBD
=> angle CBD = 50°
MAY THIS HELPS U
.•. angle APC = angle CBD
angle APC = ½angle AOC
=> angle APC = 50°
•.• angle APC = angle CBD
=> angle CBD = 50°
MAY THIS HELPS U
Abhinavj255:
yaa
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Answer:
In the given figure the angle CBD is equal to 50°.
Step-by-step explanation:
Step 1
ABCP is a cyclic quadrilateral.
A cyclic quadrilateral is one in which all the vertices of the quadrilateral lie on the circumference of a single circle.
Angle APC is equal to angle CBD.
∠APC = ∠CBD
Step 2
Angle APC = angle AOC
∠AOC = 100° ( Given )
∠APC = 50°
Therefore, ∠CBD = 50°
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