Question

in the figure o is the centre of the circle. if angle AOB= 60 degree .find angle ACB and angleADBplease give me answer fast​

Answer 1

Answer:

< ACB = 30°, <ADB = 150°

Step-by-step explanation:

< ACB is an angle on the circle and AOB is an angle at the centre subtended by same arc ADB so ACB = 1/2 AOB

Also ACBD is a cyclic quadrilateral

So oppt <s are supplementary

so ACB + ADB = 180° => ADB = 150°