in the figure o is the centre of the circle. if angle AOB= 60 degree .find angle ACB and angleADBplease give me answer fast
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Answer:
< ACB = 30°, <ADB = 150°
Step-by-step explanation:
< ACB is an angle on the circle and AOB is an angle at the centre subtended by same arc ADB so ACB = 1/2 AOB
Also ACBD is a cyclic quadrilateral
So oppt <s are supplementary
so ACB + ADB = 180° => ADB = 150°
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