Question

In the figure ,O is the middle point of AB and CD . Prove that AC =BD

Answer 1

we can giben that o is the middle term of AB amd CD
so,AO=OB,DO=OC
AB=CD(Diagnol of rectangle)
BC=DA(Opposite side of triangle)
(AB+BC)^2=(AC)2
(CD+BC)^2=(BD)^2
AC-BD=0
AC=BD

Answer 2

$\huge \boxed{\texttt{ \fcolorbox{black}{yellow}{HI BESTIE!!!}}}$

Solution

⤵⤵⤵

OB = OA { O is the mid point of AB }

AOC = BOD [ vertically opposite angles ]

OC = OD { O is the midpoint of CD }

By SAS rule

⬇⬇⬇

∆AOC ≈ ∆BOD
=> AC = BD

✨⏩ hope it helps u ⏪✨
@princessemaanu2006 ✔✔✔