Question

In the figure OA/OC=OD/OB then prove that A=C​

Answer 1

Answer:

OA/OC=OD/OB

Sides of triangle are in proportion

angle AOD=ANGLE COB.......vertically opposite angle

therefore,TRIANGLE AOD ~triangle COB...........

converse of similarity of triangle

therefore andle A=angle C.....congruent angles of similar triangle

hence proved

Answer 2

Answer:

In ΔAOB and Δ COB,

Given that OA/OC=OD/OB

So, OA/OD=OB/OC (SIDE)

∠AOD=∠COB (VERTICALLY OPPOSITE ANGLES)

Hence, Δ AOB and ΔCOB are similar

∠A=∠C (CPST)

Hence Proved..

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