In the figure on the side, BOQ and ZAOO som a linear pair. If OP and OR are their angle bisectors and POR = 90°, are A, O and collinear
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Angles ACD and DCB are a linear pair. Sum of these angles = 180 deg
ACD + DCB = 180 deg
CE is bisector of angle ACD.
CF is bisector of angle DCB.
To prove that angle ECF = 90 deg.
ECF = ECD + DCF = 1/2 ACD + 1/2 DCB
= 1/2 { angle ACD + angle DCB ] = 1/2 180 deg = 90 deg
Step-by-step explanation:
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