Question

In the figure, P and Q are the mid - points of the sides AB and BC of the rectangle ABCD.If the area of the triangle APQ is square centimetre, what is the area of the whole rectangle (in cm)?​

Answer 1

Answer:

8 times

Step-by-step explanation:

area of triangle APQ = area of triangle ABQ - Area of triangle PBQ

=> x = (1/2)AB * BQ - (1/2)PB *BQ

BQ = BC/2

PB =AB/2

=> x = (1/2)AB*BC/2 - (1/2)(AB/2)(BC/2)

=> x = AB * BC/4 - AB * BC/8

=> x = AB * BC/8

=> AB * Bc = 8x

area of rectangle = 8* area of triangle APQ

Answer 2

Answer:

8 times

Step-by-step explanation:

area of triangle APQ = area of triangle ABQ - Area of triangle PBQ

=> x = (1/2)AB * BQ - (1/2)PB *BQ

BQ = BC/2

PB =AB/2

=> x = (1/2)AB*BC/2 - (1/2)(AB/2)(BC/2)

=> x = AB * BC/4 - AB * BC/8

=> x = AB * BC/8

=> AB * Bc = 8x

area of rectangle = 8* area of triangle APQ

Hope you find it helpful .