Question

in the figure pair of similar triangles is
a)∆ABD and ∆ADE
b)∆ABE and ∆ABC
c)∆ABC and ∆ADC
d)∆ADE and ∆ABD
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Answer 1

b) In ∆ABE & ∆ABC,

Angle B = Angle [Common]

angle A= angle E [Each 90°]

∆ABE~∆CBA(AA)