In the figure PQ is a tangent to a circle with Centre O if angle OAB equal to 30 degree find angle ABP and and angle AOB
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where is a and b pt
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OAB...30
so ABP is 30 ...corresponding angle then,
ABP nd ABO are linear pair angles..
so 180-30=150
ABP..30 ABO..150
so ABP is 30 ...corresponding angle then,
ABP nd ABO are linear pair angles..
so 180-30=150
ABP..30 ABO..150
Answered by
6
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