why p forms Pf3 while N2 does not form Nf3
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Answered by
10
Nitrogen forms NF3... I don't understand the question.
Phosphorus exists as P4 in its pure form in its solid crystal form. It forms PF3 which is a trigonal pyramid.
Nitrogen exists as N2 molecule. The molecule does not react as a whole. But the atoms do react.
When Nitrogen reacts with Fluorine, it forms NF3 which is also trigonal pyramid. PF3 and NF3 have both sp3 hybridization, formed by one s orbital and 3 p orbitals.
Phosphorus exists as P4 in its pure form in its solid crystal form. It forms PF3 which is a trigonal pyramid.
Nitrogen exists as N2 molecule. The molecule does not react as a whole. But the atoms do react.
When Nitrogen reacts with Fluorine, it forms NF3 which is also trigonal pyramid. PF3 and NF3 have both sp3 hybridization, formed by one s orbital and 3 p orbitals.
kvnmurty:
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Answered by
6
The question is wrongly written.
It should be why P forms PF5 while N2 does not form NF3.
Phosphorus has vacant 3d orbitals which participate in formation of PF5.
Nitrogen does not have, so it only forms NF3.
It should be why P forms PF5 while N2 does not form NF3.
Phosphorus has vacant 3d orbitals which participate in formation of PF5.
Nitrogen does not have, so it only forms NF3.
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