Question

in the figure, PQ is parallel to RS, PAB=60° and ACS=110°, find x and y.​

Answer 1

Answer:

PQ II RS (given)

so, y=60 ° (alternative angles are equal )

QAC +ACS = 180 (angels on the same sidebof transversal are supplementary)

QAC = 180° - ACS

QAC= 180° - 110 °

QAC= 70 °

QAC + x + PAB = 180 ° ( Linear pair )

70°+ x + 60° = 180 °

x = 180° - 130°

x= 50 °

Answer 2

Answer:

answered in attachment.

Step-by-step explanation:

Hope it helps...