in the figure PQ parallel to RT find the value of a, b and c
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Hii buddy!!!
Answer =
In triangle PQR
P + Q + R = 180° 【 sum of angles of triangle is 180°】
P + 55° + 80° = 180°
P + 135° = 180°
P = 180 - 135
P = 45°
P = c = 45°
P = a 【 correspoing angle】
a = 45°
80° + a + b = 180° 【linear pair】
80° + 45° + b = 180°
125° + b = 180°
b = 180 - 125
b = 55°
Hope helps
Mark me brainlest
Answer =
In triangle PQR
P + Q + R = 180° 【 sum of angles of triangle is 180°】
P + 55° + 80° = 180°
P + 135° = 180°
P = 180 - 135
P = 45°
P = c = 45°
P = a 【 correspoing angle】
a = 45°
80° + a + b = 180° 【linear pair】
80° + 45° + b = 180°
125° + b = 180°
b = 180 - 125
b = 55°
Hope helps
Mark me brainlest
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