Question

In the figure PQ=QR angle QPR =48 degree angle SRP = 18 degree then find angle PQR​

Answer 1

Answer:

Here triangle PQR is isosceles.

angle QPR= QRP= 48

By angle sum property:

P+Q+R= 180. THESE ARE ANGLE

48+Q+48=180

Q= 180-96

Q= 84°

Step-by-step explanation:

hope help u

Answer 2

Given,

PQ = QR

∠QPR = 48°

∠SRP = 18°

To find,

We have to find ∠PQR.

Solution,

The measure of ∠PQR  in Δ PQR is 84°.

We can simply find the measure of ∠PQR by using the properties of the triangle.

    It is given that PQ = QR, then ∠R = ∠P

     as Equal sides of a triangle have equal opposite angles.

      ∠QPR = ∠QRP = 48°

By using the Angle sum property in Δ PQR, we get,

         ∠P + ∠Q + ∠R = 180°

        48° + ∠Q + 48° = 180°

                           ∠Q = 180° - 48° - 48°

                           ∠Q = 180° - 96°

                           ∠Q = 84°

Hence, the measure of ∠PQR in Δ PQR is 84°.