In the figure PQ=QR angle QPR =48 degree angle SRP = 18 degree then find angle PQR and angle QRS
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Step-by-step explanation:
Given, in △PQR,PQ=PR
Therefore, △PQR is an isosceles triangle with equal base angles, ∠Q=∠R.
Exterior ∠R=100
o
Therefore, PRQ=80
o
As angles Q and R are equal, ∠PQR=80
o
∠P+∠Q+∠R=180
o
∴∠P=20
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i.e. ∠QPR=20
o
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