In the figure, PQ = QR = RS = SP = SQ =6cm and PT = RT = 14cm.
Then length of st is
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Step-by-step explanation:
In the figure, PQ = QR = RS = SP = SQ =6cm and PT = RT = 14cm.
Then length of st is
In the PQR, S and T are points on sides PQ and PR respectively such that
ST∥QR. If PT = 1 cm; PS=1.5 cm and SQ=3 cm, then find RTANSWER
Given:
ST∥QR
PT= 4 cm
TR = 4cm
In △PST and △PQR,
∠SPT=∠QPR(Common)
∠PST=∠PQR (Corresponding angles)
△PST∼△PQR(By AA similarity criterion)
We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides.
area△PQRarea△PST=PR2PT2
area△PQRarea△PST=(PT+TR)242
area△PQRarea△PST=(4+4)216=8216=6416=41
Thus, the ratio of the areas of △PST and △PQR is
1:4.
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