Question

In the figure, PQR ia a right angled triangle right angled at P . Semicircles are drawn with PQ PR QR as diameter . If PQ =6cm PR=8vm then area of the shaded region is

Answer 1

Answer:

Area of circle with QR as diameter =π(52)2=25π2㎠

Area of semi circle with diameter PR

=π(42)2=8π㎠

Area of semi circle with PQ

diameter

=π(32)2=9π2㎠

Area of triangle PQR=12×6×8=24㎠

Area of shaded regions=(8π+9π2+24)−(25π2)=12.5π+24−12.5π=24㎠

I HOPE THIS IS HELPFUL FOR U GUYS THANK U

AND PLZ BUDDY MARK THIS AS BRAINLIEST...