Question

In the figure ,PQRS is a cyclic Quadrilateral PS=SR and PQ is a diameter. Find Angle PRS

Answer 1

Angle PRQ= 90
PRQ+RPQ+RQP=180
RQP=50
RQP+PSR=180
PSR=130
ITS ISOLATED triangle
so PRS=25

Answer 2

We know that is case of cyclic quadritral sum of opposite angles are 180 degree
So,
we also know that angle in a semi circle is 90 degree so Now from the above equation-


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