Question

in the figure PR and QS are two diameters is PQ=RS

Answer 1

Yes , PQ is equal to  RS
  Considering a circle, where PR and QS being a diameter.
  Let centre of circle be O
  Two triangles are formed:  POQ and SOR
   In triangles POQ and SOR
   PO = OR (Radius of circle)
   OS = OQ (Radius of circle)
   Angle POQ = Angle SOR (Vertically opposite angles are always equal)
Hence triangle POQ is congruent to triangle SOR (By Side Angle Side Axiom)
PQ = RS (By C.P.C.T.C) (Proved)

Answer 2

Answer:

where is the diagram

Step-by-step explanation: