In the figure,prove that d=a+b+c
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Answered by
1
Answer:
since d is an inner vertex angle so a+b+c = d
Answered by
3
Answer:
join BD and expand upor E
then,external angle ADE of the triangle ABD
=angle DAB+angle ABD
again,external angle CDE of the triangle BDC
= angle DBC+angleBCD
so,
ADE+CDE=DAB+ABD+DBC+BCD
ADC=DAB+ABC+BCD
d=a+b+c
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