Question

In the figure,
PS-3, SQ - 6, QR=S,PT =* and TR = y. Give any two pairs of
values of x and y such that line ST | side QR.​

Answer 1

Answer:

Since ST || QR:

PS/SQ = PT/TR

By Basic Proportionality Theorem.

=> 3/6 = x/y

=> x/y = 1/2

=> y = 2x

Two pairs:

When x = 1

y = 2x = 2

#Pair1: 1, 2

When x =2

y = 2x = 4

#Pair2: 2,4

Hope it Helps!!