Question

In the figure PT is the tangent to the circle at P and OR is the diameter of the circle. If angle RPT =50degree find angle QRP...??

Answer 1

Given :- In the figure PT is the tangent to the circle at P and QR is the diameter of the circle. If angle RPT =50degree find angle QRP...??

Solution :-

→ ∠RPT = 50° (given)

So,

→ ∠PQR=50° {Alternate segment theorem .}

and,

→ ∠QPR = 90° {Angle in Semicircle.}

therefore, in ∆PQR, we have,

→ ∠QPR + ∠PQR + ∠QRP = 180° (Angle sum Property.)

→ 90° + 50° + ∠QRP = 180°

→ 140° + ∠QRP = 180°

→ ∠QRP = 180° - 140°

→ ∠QRP = 40° (Ans.)

Learn more :-

PQ and XY are two chords of a circle such that PQ = 6 cm and XY = 12 cm and PQ||XY. If the distance between the chords i...

https://brainly.in/question/24793483

PQRS is a cyclic quadrilateral with PQ = 11 RS = 19. M and N are points on PQ and RS respectively such that PM = 6, SN =...

https://brainly.in/question/27593946

Answer 2

Answer:

angle QRP = 50 degree

please mark me as brainliest