in the figure seg AB and cD intersect at point p AP×BP=CP×DP then prove angle CAB congruent CDB please help me
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cosider triangle apc and bpd
it is sas congruency rule
so corresponding angles are equal
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Step-by-step explanation:
Triangles are similar if: SAS (side angle side) - Two pairs of sides in the same proportion and the included angles are congruent. → Δ CAP ~ Δ BDP → ∠ CAB ≅ ∠ CDB
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