Question

In the figure
seg AB is parallel to Seg CD
angle A =75 and angle C =35°
find the value of x ,y and z


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Answer 1

Answer:

It is given that AB || CD and BC is a transversal From the figure we know that ∠ABC = ∠BCD

So we get x = 35 It is also given that AB || CD and AD is a transversal

From the figure we know that ∠BAD = ∠ADC So we get z = 75

According to the △ ABO

We can write ∠ABO + ∠BAO + ∠BOA = 180o

By substituting the values xo + 75o + yo = 180o 35o + 75o + yo = 180o

On further calculation yo = 180o – 35o – 75o By subtraction yo = 180o – 110o yo = 70o

Therefore, the value of x, y and z is 35, 70 and 75.

Answer 2

Answer:

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