In the figure shown a smooth ring is connected to rod AB, while rod CD passes through ring. At the given instant angular velocity of rod AB about hinge A is and, instantaneous angular velocity of rod CD about hinge C is
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given = refer the given diagram
ring is connected to rod AB,
rod CD passes through ring.
rod CD about hinge C
solution = velocity have same component. velocity of contact point on rod CD and ring should have same component of velocity along normal to rod CD
BC(ω) = 2(BCcosθ)ω cosθ
ω " = 2ωcos²θ
ω"= 3/2rad/s
so the angularr velocity of rod AB about hinge A is 3/2rad/s
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