In the figure the diameter of the circle is 20cm.
Two parallel chords are drawn in the circle
They
are AB = 16 cm and CD = 12 cm. Find the
distance between
these chords.
Answers
Answered by
1
Let the parallel chords be AB = 16 cm and CD = 12 cm in the circle of radius R = 10 cm. Let the midpoint of AB be P, that of CD, Q and the center be O.
OP = [10^2–8^2]^0.5 = 6 cm
OQ = [10^2–6^2]^0.5 = 8 cm
Hence PQ = 6+8 = 14 cm
Answered by
2
Answer:
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