Question

in the figure tm bisects rs and sn bisects rt further it has been given that the perpendicular are also equal is snt congruent tms​

Answer 1

Step-by-step explanation:

In SNT and TMS

angle N=angle M(90 each) ....R

ST=ST(coman) ....h

RS=NT

2MS=2NT

MS=NT ....s

So,

SMT congruent TMS

Answer 2

Answer:

Given: In the figure it is given that TM bisects RS and SN bisects rt further it has been given that the perpendicular are also equal is SNT congruent TMS

To find: prove that triangular SNT = triangular TMS

Step-by-step explanation:

Here in the figure, it is given that tm is perpendicular to RS and SN is perpendicular to RT

therefore, in Δ SNT and ΔTMS

seg MS ≅ seg NT( opposite sides)

∠SNT≅∠TMS (each 90 degree)

Seg TS ≅ Seg ST(common sides in the figure)

therefore, ΔSNT ≅ΔTMS

Hence it is proved that ΔSNT ≅ΔTMS is true and perpendicular is also equal.

#SPJ2