in the figure triangle abc is right angled at a. q and r are points on bc produced and bc respectively . there is a point p such that qp parallel ab and rp parallel ac .find p
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Step-by-step explanation:
Given : < A = 90°
To Find : < P
Solution : Since AC || PS where AB is transversal.
< BAC = < BSR [Corresponding angles]
< BSR = 90°
Since PQ || AB where PS is transversal.
< BSR = < RPQ [Alternate angles]
< RPQ = 90°
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