In the figure two circles with centres P and Q intersect at R and S. prove that PQR=PSQ
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ps= pr (radius of same circle)
qr=qs (radius of same circle)
pq=pq (common)
by sss criteria PQR=PQS
qr=qs (radius of same circle)
pq=pq (common)
by sss criteria PQR=PQS
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