In the figure two congruent circles touch each other externally and also
touches the sides of the rectangle ABCD. If AB = 28 cm and BC = 14 cm,
find the area of shaded region
Answers
Answer:
Area of rectangle ABCD = L*B
Area of rectangle ABCD = L*BLength = 28 cm(AB)
Area of rectangle ABCD = L*BLength = 28 cm(AB)Breadth = 14 cm(BC)
Area of rectangle ABCD = L*BLength = 28 cm(AB)Breadth = 14 cm(BC)Area of the rectangle = 28*14
Area of rectangle ABCD = L*BLength = 28 cm(AB)Breadth = 14 cm(BC)Area of the rectangle = 28*14 = 392 cm.square
Area of rectangle ABCD = L*BLength = 28 cm(AB)Breadth = 14 cm(BC)Area of the rectangle = 28*14 = 392 cm.squareArea of a circle = 22/7 * r.square
Area of rectangle ABCD = L*BLength = 28 cm(AB)Breadth = 14 cm(BC)Area of the rectangle = 28*14 = 392 cm.squareArea of a circle = 22/7 * r.squareDiameter of a circle = 28/2
Area of rectangle ABCD = L*BLength = 28 cm(AB)Breadth = 14 cm(BC)Area of the rectangle = 28*14 = 392 cm.squareArea of a circle = 22/7 * r.squareDiameter of a circle = 28/2 = 14 cm
Area of rectangle ABCD = L*BLength = 28 cm(AB)Breadth = 14 cm(BC)Area of the rectangle = 28*14 = 392 cm.squareArea of a circle = 22/7 * r.squareDiameter of a circle = 28/2 = 14 cm∴ Area of the circle = 22/7*14
Area of rectangle ABCD = L*BLength = 28 cm(AB)Breadth = 14 cm(BC)Area of the rectangle = 28*14 = 392 cm.squareArea of a circle = 22/7 * r.squareDiameter of a circle = 28/2 = 14 cm∴ Area of the circle = 22/7*14 = 44 cm.square
Area of rectangle ABCD = L*BLength = 28 cm(AB)Breadth = 14 cm(BC)Area of the rectangle = 28*14 = 392 cm.squareArea of a circle = 22/7 * r.squareDiameter of a circle = 28/2 = 14 cm∴ Area of the circle = 22/7*14 = 44 cm.squareSo, Area of two circles = 44*2
Area of rectangle ABCD = L*BLength = 28 cm(AB)Breadth = 14 cm(BC)Area of the rectangle = 28*14 = 392 cm.squareArea of a circle = 22/7 * r.squareDiameter of a circle = 28/2 = 14 cm∴ Area of the circle = 22/7*14 = 44 cm.squareSo, Area of two circles = 44*2 = 88 cm.square
Area of rectangle ABCD = L*BLength = 28 cm(AB)Breadth = 14 cm(BC)Area of the rectangle = 28*14 = 392 cm.squareArea of a circle = 22/7 * r.squareDiameter of a circle = 28/2 = 14 cm∴ Area of the circle = 22/7*14 = 44 cm.squareSo, Area of two circles = 44*2 = 88 cm.square∴ Area of the shaded region = Area of rectangle - Area of the two circles
Area of rectangle ABCD = L*BLength = 28 cm(AB)Breadth = 14 cm(BC)Area of the rectangle = 28*14 = 392 cm.squareArea of a circle = 22/7 * r.squareDiameter of a circle = 28/2 = 14 cm∴ Area of the circle = 22/7*14 = 44 cm.squareSo, Area of two circles = 44*2 = 88 cm.square∴ Area of the shaded region = Area of rectangle - Area of the two circles =392-14
Area of rectangle ABCD = L*BLength = 28 cm(AB)Breadth = 14 cm(BC)Area of the rectangle = 28*14 = 392 cm.squareArea of a circle = 22/7 * r.squareDiameter of a circle = 28/2 = 14 cm∴ Area of the circle = 22/7*14 = 44 cm.squareSo, Area of two circles = 44*2 = 88 cm.square∴ Area of the shaded region = Area of rectangle - Area of the two circles =392-14 =304
thanks for the answer mate mark and FØŁŁØW me