Question

In the figure,two person are standing at the opposite direction P &Q of the tower If the height of the tower is 60m then the distance between the two person

Answer 1

Answer: The distance between the two persons would be 60(sqrt3+1) m.

Step-by-step explanation:

ABP and ABQ are the two right-angled triangle in the question figure.

Using the trigonometric ratios as follow:

In triangle ABP,

cot30=base/height= PB/AB

PB= AB*cot30

PB= 60*sqrt3 m

In triangle ABQ,

cot45=BQ/AB

BQ=AB*cot45

BQ=60*1

BQ=60 m

The distance between the two persons, P and Q= PQ= PB+BQ

PQ=60*sqrt3+60= 60(sqrt3+1) m

Answer 2

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