Question

in the figure, two triangles ABC and dbc are on the same base by in which triangles A= triangles D=90dere ​

Answer 1

Given triangles ABC and DBC are on the same base BC.

Consider, Δ’s ABC and DBC

∠A = ∠D = 90° (Given)

∠AEB = ∠DEC (Vertically opposite angles are equal)

Hence ΔABC ~ ΔDBC (AA similarity theorem)

==> AE/DE = BE/CE

∴ AE × CE = BE × DE ( Hence Proved)

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