Question

In the figure, ZOPR=90º, seg PM 1 seg QR and 0-M-RPM=10.
OM=8; find QR.​

Answer 1

Step-by-step explanation:

In∆ QPR

ZQPR=90°...(given)

segPM l hypotenuse QR ....(given)

by theorem of geometric mean,

PM2=QM×MR

10 2 =8×MR

MR=100/8

MR=12.5

QR=QM+MR .....(Q-M-R)

QR=8+12.5

QR=20.5