Question

in the figures, XT bisects angle MXY and angle MXY. is MZ = YZ? give reasons to support your answer.




please answer fastest as it possible....​

Answer 1

Given,

Given,XT bisects angle MXY and MZY.

Given,XT bisects angle MXY and MZY.prove : MZ = YZ

Given,XT bisects angle MXY and MZY.prove : MZ = YZnotice that XYZ and XMZ form a triangle.

Given,XT bisects angle MXY and MZY.prove : MZ = YZnotice that XYZ and XMZ form a triangle.hence,

Given,XT bisects angle MXY and MZY.prove : MZ = YZnotice that XYZ and XMZ form a triangle.hence,∆XYZ congruent to ∆XMZ

Given,XT bisects angle MXY and MZY.prove : MZ = YZnotice that XYZ and XMZ form a triangle.hence,∆XYZ congruent to ∆XMZXZ = XZ (common side)

Given,XT bisects angle MXY and MZY.prove : MZ = YZnotice that XYZ and XMZ form a triangle.hence,∆XYZ congruent to ∆XMZXZ = XZ (common side)angle YXZ = angle MXZ (as XT bisects angle MXY)

Given,XT bisects angle MXY and MZY.prove : MZ = YZnotice that XYZ and XMZ form a triangle.hence,∆XYZ congruent to ∆XMZXZ = XZ (common side)angle YXZ = angle MXZ (as XT bisects angle MXY)angle MZY = angle YZX (as XT bisects angle MZY)

Given,XT bisects angle MXY and MZY.prove : MZ = YZnotice that XYZ and XMZ form a triangle.hence,∆XYZ congruent to ∆XMZXZ = XZ (common side)angle YXZ = angle MXZ (as XT bisects angle MXY)angle MZY = angle YZX (as XT bisects angle MZY)therefore both the triangles are congruent by ASA congruency.

Given,XT bisects angle MXY and MZY.prove : MZ = YZnotice that XYZ and XMZ form a triangle.hence,∆XYZ congruent to ∆XMZXZ = XZ (common side)angle YXZ = angle MXZ (as XT bisects angle MXY)angle MZY = angle YZX (as XT bisects angle MZY)therefore both the triangles are congruent by ASA congruency.MZ = YZ by CPCT (corresponding parts of congruent triangles)

Given,XT bisects angle MXY and MZY.prove : MZ = YZnotice that XYZ and XMZ form a triangle.hence,∆XYZ congruent to ∆XMZXZ = XZ (common side)angle YXZ = angle MXZ (as XT bisects angle MXY)angle MZY = angle YZX (as XT bisects angle MZY)therefore both the triangles are congruent by ASA congruency.MZ = YZ by CPCT (corresponding parts of congruent triangles)Hope it helps

Given,XT bisects angle MXY and MZY.prove : MZ = YZnotice that XYZ and XMZ form a triangle.hence,∆XYZ congruent to ∆XMZXZ = XZ (common side)angle YXZ = angle MXZ (as XT bisects angle MXY)angle MZY = angle YZX (as XT bisects angle MZY)therefore both the triangles are congruent by ASA congruency.MZ = YZ by CPCT (corresponding parts of congruent triangles)Hope it helpshave a great day

Answer 2

GIVEN :

XT bisects ∠MXY.

TO PROVE :

MZ = YZ

WkT (we know that):

» In ΔXYZ

• XY/YZ = XM/MZ (angle bisector theorem)
• 1 = XM/MZ (XY = YZ)
• MZ = YZ

HENCE proved, MZ = YZ