in the find the Pythagorean triplet whose one member is 35
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35=6^2-1 (n^2-1) form
n=6
other two numbers
2n=2×6=12
n^2+1=6^2+1=37
n=6
other two numbers
2n=2×6=12
n^2+1=6^2+1=37
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