Question

in the first order reaction AB50% of given sample of compound decomposes in 40 minutes.calculate the rate constant of the reaction?​

Answer 1

Answer: The rate constant of the given reaction is 0.017325 min^-1

Explanation:

• Half life of first order reaction is given by = $\frac{0.693}{k}$    ,    where k is rate constant of reaction.
• As half life of sample is given = 40 min
• Applying formula of half life & rearranging formula in terms of k

                k = (0.693/40) min^-1

                k = 0.017325 min^-1

               

Answer 2

HeYa!

The rate constant of the given reaction is 0.017325 min^-1

Explanation:

Half life of first order reaction is given by =    ,    where k is rate constant of reaction.

As half life of sample is given = 40 min

Applying formula of half life & rearranging formula in terms of k

                k = (0.693/40) min^-1

                k = 0.017325 min^-1

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