in the follow diagram Mayuri is house is at a Neha's house at 'B' and their school is at 'C' Mayuri first goes to Neha's house then they both go to school the distance travelled by Mayuri is shown in the picture Mayuri required 25 minutes to reach the school then find the speed of Mayuri?
plz helppppp
i mark him brainlist....
Attachments:
Answers
Answered by
7
As total distance travelled by Mayuri is 1200m+ 900m as she first goes from Neha's home then school.
Further Speed = Distance/ time
so, = 2100/25 min
speed = 84 m/s
Thank you
Further Speed = Distance/ time
so, = 2100/25 min
speed = 84 m/s
Thank you
Answered by
7
TIME FOR MAYURI= 25 MIN
DISPLACEMENT O MAYURI= 900m
total path length =
= 900+1200+1500
= 3600
speed= 3600/25
= 144 ms
SPEED IN KM/H
144× 5/18
= 40 KM/H
DISPLACEMENT O MAYURI= 900m
total path length =
= 900+1200+1500
= 3600
speed= 3600/25
= 144 ms
SPEED IN KM/H
144× 5/18
= 40 KM/H
Answered by
4
TIME FOR MAYURI= 25 MIN
DISPLACEMENT O MAYURI= 900m
total path length =
= 900+1200+1500
= 3600
speed= 3600/25
= 144 ms
SPEED IN KM/H
144× 5/18
= 40 KM/H
DISPLACEMENT O MAYURI= 900m
total path length =
= 900+1200+1500
= 3600
speed= 3600/25
= 144 ms
SPEED IN KM/H
144× 5/18
= 40 KM/H
Similar questions