Question

In the following APs, find the missing terms in the boxes

1)2,_,26
2) _,13,_,3
3)5,_,_,91/2
4)-4,_,_,_,_,6
5)_,38,_,_,_,-22​

Answer 1

Step-by-step explanation:

1) 2_26

its Formula is

$\frac{a1 + a3}{2} = a2$

you can Answer Like This So First Will Be

1) 2,14,26

2)21,13,8,3

3)A=5

A4=91/2

A4=A+(4-1)d

91/2=5+3d

$3d = \frac{91}{2} - 5 \\ 3d = \frac{91 - 10}{2} \\ 3d = \frac{81}{2} \\ d = \frac{27}{2}$

Hence Ap is 5,37/2,32,91,2

4)a=-4

A6=6

A6= a +(n-1)d

6=-4+(6-1)d

10=5*d

d=2

so Ap is

4)-4,-2,0,2,4,6

5)A2=38

A6=-22

A2=a+d

A6=a+5d

By Elimination Method

-4d=60

d=-12

Hence Ap Is 60,38,26,14,2,-12,-22