Question

in the following change
3Fe+4H2O----)Fe3O4+4H2
if the atomic weight of iron is 56 then its Equivalent weight will be

Answer 1

Fe3O4

let oxidation state of fe is x

3x -8 = 0

3x = 8

x= 8/3

So n factor = 8/3


Equivalent weight = atomic mass/n factor

= 56/ 8/3 = 56× 3/8 = 21

Answer 2

Given that,

A chemical reaction, $3Fe+4H_2O\rightarrow Fe_3O_4+4H_2$

The atomic weight of iron is 56

To find,

Its equivalent weight.

Solution,

The formula used to find the equivalent weight is equal to :

$\text{equivalent weight}=\dfrac{\text{atomic mass}}{\text{n-factor}}$

Let us consider that the oxidation state of Fe is x. So,

$3x-8=0\\\\x=\dfrac{8}{3}$

It means that the value of x is 8/3.

Using the above formula,

$\text{equivalent weight}=\dfrac{56}{\dfrac{8}{3}}\\\\\text{equivalent weight}=21$

So, the equivalent weight will be 21.