Question

In the following diagram , the conducting shell A is given a charge q and conducting shell B is earthed . The electric flux linked with Gaussian surface S1 and S2 respectively are​

Answer 1

Given:

The conducting shell A is given a charge q and conducting shell B is earthed .

To find:

Electrostatic flux linked with Gaussian surface S1 and S2.

Calculation:

Let flux be denoted as $\phi$.

The Gaussian Surface S1 encloses charge q.

Initially -q had been inducted in the S1 surface, but. the charge gets earthened. Hence net charge enclosed is +q.

$\boxed{ \therefore \: \phi1 = \dfrac{q}{ \epsilon_{0}} }$

The Gaussian Surface S2 also encloses net charge q.

$\boxed{ \therefore \: \phi2 = \dfrac{q}{ \epsilon_{0}} }$

So, correct Option is:

$\boxed{ \sf{ \red{ \large{Option \: 3}}}}$

Answer 2

Answer:

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Explanation:

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