Math, asked by kavyakhandelwapatw7e, 1 year ago

in the following figure ab is parrel to cd. find the measure of angle boc

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Answered by saurabhsinghbihari

,hope it helps you dearrrrrrrrrrrr

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kavyakhandelwapatw7e: nhi but last mai acd=angle bcd= 180 degree hai

saurabhsinghbihari: is c midpoint of AB

kavyakhandelwapatw7e: ok

kavyakhandelwapatw7e: yes

saurabhsinghbihari: plz send complete and correct question

kavyakhandelwapatw7e: ok

kavyakhandelwapatw7e: If a ray CD stands on a line AB, then prove that
Angle ACD= angle BCD=180°

kavyakhandelwapatw7e: tell

saurabhsinghbihari: angle ACD +angle BCD= 180 degree or that

kavyakhandelwapatw7e: degree

Answered by slicergiza

Answer:

60°

Step-by-step explanation:

Given,

CD ║ AB

⇒ CD ║ AF ( shown in the given diagram ),

Let ∠x and ∠DCE are linear pairs,

⇒ ∠x + m∠DCE= 180°,

⇒ ∠x + 75° = 180° ( by the diagram ),

⇒ ∠x = 180° - 75° = 105°,

By the alternate interior angle theorem,

∠x ≅ ∠1,

⇒ m∠x = m∠1

⇒ m∠1 = 105°,

Now, by the vertically opposite angle theorem,

∠1 ≅ ∠BEO,

⇒ m∠BEO = 105°,

Now, m∠EBO = 15°,

∵ BEO is a triangle,

⇒ m∠EBO + m∠BEO + m∠BOE = 180°,

⇒ 15° + 105° + m∠BOE = 180°,

⇒ 120° + m∠BOE = 180°,

⇒ m∠BOE = 60°,

⇒ m∠BOC = 60°,

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