In the following figure ABCD is a rectangle with side 8cm and 4cm . find the area of triangle ABCD and Triangle CAD.
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4
area of rectangle ABCD = l × b
= 8 × 4
= 32cm square
area of triangle CAD= half × base × height
= half × 8 × 4
= 16cm sq.
= 8 × 4
= 32cm square
area of triangle CAD= half × base × height
= half × 8 × 4
= 16cm sq.
Answered by
0
area of ABCD =l×b=8×4=32cmsq
area of CAD=1/2×b×h=8×4=32cmsq
area of CAD=1/2×b×h=8×4=32cmsq
dhwishi23:
its area of cad be 16cmsq
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