In the following figure AE = BC and AE parallel to BC.If AB=ED and angle A = 102 degree. Then find angle B ,angle ECD , angle CED and angle AED.
Plzzz answer fast i will mark it as brainliest
Attachments:
Answers
Answered by
2
B=72
ECD=72
CED=36
AED=144
Hope they are correct
ECD=72
CED=36
AED=144
Hope they are correct
passo:
write full explanation
Answered by
9
As the figure is a parallelogram,
∠a+∠b=180°
so,∠b=78°
∠ECD=78°(since ab ║ce)
∠CED=78°
∠AED=24°
∠a+∠b=180°
so,∠b=78°
∠ECD=78°(since ab ║ce)
∠CED=78°
∠AED=24°
Similar questions