Math, asked by passo, 1 year ago

In the following figure AE = BC and AE parallel to BC.If AB=ED and angle A = 102 degree. Then find angle B ,angle ECD , angle CED and angle AED.
Plzzz answer fast i will mark it as brainliest

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Answered by ark1510
2
B=72
ECD=72
CED=36
AED=144
Hope they are correct

passo: write full explanation
ark1510: in abce opp. wider are equal hence it's a parllelogram
ark1510: sides*
ark1510: hence a+b=180 b=72
ark1510: ecd=108 hence ecd=72
passo: wrong
ark1510: how?
Answered by manopollachi
9
As the figure is a parallelogram,
∠a+∠b=180°
so,∠b=78°
∠ECD=78°(since ab ║ce)
∠CED=78°
∠AED=24°
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