Question

in the following figure angle axy=angle ayx.if bx/ax=cy/ay show that triangle abc is isosceles

Answer 1

Given,
∠AXY = ∠AYX
⇒AX = AY

Also, BX/AX = CY/AY
⇒BX/AX + 1 = CY/AY + 1
⇒BX+AX/AX = CY+AY/AY
⇒AB/AX = AC/AY
⇒AB/AY = AC/AY [∵ AX = AY]
⇒AB = AC

Thus, the given triangle is isosceles.

Answer 2

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