Math, asked by marriam, 1 year ago

In the following figure DE parallel to BC AD=x+4 DB=x+3
AE=2x-1 EC=x+1. find x=?

Answers

Answered by lucky467540
1

Answer:

2259 +  \times  \times 3 \times 5 \times  = 3 \times x1 = 266 -

Answered by NaniNarendra
5

Answer:

Step-by-step explanation:

AD=X+4

DB=X+3

AE=2X-1

EF=X+1

X+4/X+3=2X-1/X+1

(X+4)(X+1)=(2X-1)(X+3)

X(X+1)+4(X+1)=2X(X+3)-1(X+3)

X^2+X+4X+4=2X^2+6X-X-3

X^2+5X+4=2X^2+5X-3

2X^2-X^2+5X-5X-3-4=0

X^2-7=0

X^2=7

X=+√7,-√7

X=√7

X=-√7

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